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-1 x tan x + C
If we solve it as ... \ / / \ | 1 / x |------- / | 2 / | 1 + x / / \ / \ / / / 1 | 2x / = ---|------- / 2x | 2 | 1 + x \ / / \ / \ 1 / 2 = --- ln (1 + x ) + C 2x / \ / \ / \ / \
Here x is before the integration sign. So here we have to find only the integration of 1/(1+x^2) / | 1 x |------- | 2 | 1 + x / -1 = x . tan x + C -1 = x tan x + C