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Both are true
First take option (a) _ _ 5 | 1 | | --- | |_ 0 _|
We know that solution of 1/0 is undefined. So solution of (1/0)^-5 will be undefined to power -5 which will be still undefined.
= Undefined .............. (i) Now take option (b) 1 = --- 5 0 1 = --- 0 = Undefined .............. (ii) From (i) and (ii) _ _ 5 | 1 | 1 | --- | = --- = Undefined |_ 0 _| 5 0
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1/3 -2/3 2n - 2n -------------- = ? -2/3 2n
_____________________ / _____________ / / ____ / / / 2 / 4 / 4 . / 4 / \/ \/ / -------------------- / 3 \/ 2