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Give the exponential function whose 2nd derivative is equal to function itself = ...?

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Answer
     x  -x
    e, e    both
Explanation
                           x            x
We know the derivative of e   is again e  (i.e itself)
                     x     d   x   x
First derivative of e   = --- e = e
                          dx
                      x    d   x
Second derivative of e  = --- e
                           dx

Therefore e^x is the function whose 2nd derivative is itself.

                           -x            -x
We know the derivative of e   is again -e  
                     -x    d   -x   -x
First derivative of e   = --- e  = -e
                           dx
                      -x   d   -x    -x
Second derivative of e  = --- -e  = e
                          dx

Therefore e^-x is the function whose 2nd derivative also is itself.Therefore e^x and e^-x both's 2nd derivative is equal to the function itself.

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